Figure 3From: A model combining cell physiology and population genetics to explain Escherichia coli laboratory evolutionPhysiological responses to changes in X. A. Growth rate (μ) vs. X. The points (•) were obtained solving equations (1) to (3) for different values of X (the values of the other parameters as in Figure 2). They were fitted to a rectangular hyperbola: μ = μ max X/(Kμ + X) using the transformation: X/μ = X/μ max + Kμ/μ max . The resulting hyperbola (μ max = 2.108 and Kμ = 3.586) is the curve (—) joining the points. B. vs. μ. (the arithmetic mean of the initial and final cell volume in a cell cycle) and μ are obtained for different values of X as described in (A). Their values (•) are represented together with the exponential fit: , with 0 = 0.4734 and c = 0.5519.Back to article page